if a=cos2 and b=sin 7 ,then
a)a>0,b >0
b)ab<0
c)a>b
d)a
Answer (1)
Student Expert
25th Mar, 2020
Hi
The correct option is (c) ab <0 dear.
Explanation is provided below :-
cos2<0 as we know cos(pi/2)=0 and (pi/2)is somewhere around 1.57
so it lies in the second quadrant (where values lie for 1 to 4.71).
In second quadrant, cos value is negative .
sin7>0 as we know sin(pi/2)=1 and (pi)is somewhere around 6.28
so after one complete rotation it lies in the first quadrant (where values lie for 0 to 1.57) .
In first quadrant, sin value is positive.
so, ab<0 ,as a negative number multiplied by a positive number gives negative number .
Thankyou
The correct option is (c) ab <0 dear.
Explanation is provided below :-
cos2<0 as we know cos(pi/2)=0 and (pi/2)is somewhere around 1.57
so it lies in the second quadrant (where values lie for 1 to 4.71).
In second quadrant, cos value is negative .
sin7>0 as we know sin(pi/2)=1 and (pi)is somewhere around 6.28
so after one complete rotation it lies in the first quadrant (where values lie for 0 to 1.57) .
In first quadrant, sin value is positive.
so, ab<0 ,as a negative number multiplied by a positive number gives negative number .
Thankyou
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