If all the letters of word engineers be written at random what is the probability that all the letters e are found together
Hello Student,
First of all the word is ENGINEER.
Let total ways of arranging this word are A
Now A = 8! / 3! * 2! ; A = 3360
Now let all E are taken together as a single unit , i.e. now total words in engineer left are 6.
Let ways of arranging now the word with all E together are B
So B = 6! / 2! : B = 360
Now probability of getting all E together is given by P.
P = B/A = 3/28
Hello Student,
combine all E's together in one group and consider it as a single unit
now there are 6 groups
arranging 6 groups in all possible ways = 6!/2!
[divide by 2! coz N's are repeated]=360
total no. of ways = 8! / [3! * 2!]=3360
prob = 360/3360=36/336=0.107
Hope i was able to answer your question.
Hello,
consider [EEE] it as a one block to be permuted along with NGINR
favorable ways = 6!/2! = 360
total ways = 8!/3!2! = 3360
Pr = 360/3360 = 3/28
Generally, This type of questions can be solved like a dice question, what's the probability of rolling a 1 on a 6 sided dice, 1/6
Engineer is an 8 letter word and there are 3 E's, so 3/8.
