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if alpha and beta are the zeroes of the quadratic polynomials ax^2+bx+c,Then find the value of alpha ^2+beta^2


Pushpa Mallappa 4th Apr, 2021
Answer (1)
Vidya Mandadi 4th Apr, 2021

Hello there,

Solution for your question is

(alpha)^2+(beta)^2

(alpha+beta)^2-2)(alpha)(beta)=(alpha)^2+(beta)^2

(alpha+beta)= -b/a

(alpha)(beta)= c/a

Now, substituting the above values in the equation we get,

(-b/a)^2 - (2*(c/a))= (alpha)^2+(beta)^2

So, b^2/a^2 - (2(c/a)) = (alpha)^2+(beta)^2

(b^2-2ac)/ (a^2) = (alpha)^2+(beta)^2

Thank you.

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