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if alpha and beta are zeroes of the polynomial ax^2+bx+c


Pushpa Mallappa 4th Apr, 2021
Answer (1)
Vidya Mandadi 4th Apr, 2021

Hello there,

The question you asked is quite incomplete. However if you are looking for this then

Solution for your question is

(alpha)^2+(beta)^2

(alpha+beta)^2-2)(alpha)(beta)=(alpha)^2+(beta)^2

(alpha+beta)= -b/a

(alpha)(beta)= c/a

Now, substituting the above values in the equation we get,

(-b/a)^2 - (2*(c/a))= (alpha)^2+(beta)^2

So, b^2/a^2 - (2(c/a)) = (alpha)^2+(beta)^2

(b^2-2ac)/ (a^2) = (alpha)^2+(beta)^2

Thank you.

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