if alpha and beta are zeroes of the polynomial ax^2+bx+c
Answer (1)
4th Apr, 2021
Hello there,
The question you asked is quite incomplete. However if you are looking for this then
Solution for your question is
(alpha)^2+(beta)^2
(alpha+beta)^2-2)(alpha)(beta)=(alpha)^2+(beta)^2
(alpha+beta)= -b/a
(alpha)(beta)= c/a
Now, substituting the above values in the equation we get,
(-b/a)^2 - (2*(c/a))= (alpha)^2+(beta)^2
So, b^2/a^2 - (2(c/a)) = (alpha)^2+(beta)^2
(b^2-2ac)/ (a^2) = (alpha)^2+(beta)^2
Thank you.
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