if an ideal gas at 1 atm pressure, is spreading from 20 cm3 to 50 cm3 at constant temp. then find the final pressure.
Also Check: Crack JEE Main 2025 - Join Our Free Crash Course Now!
JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQs | Video Lectures
JEE Main 2025: Preparation Guide | High Scoring Topics | Study Plan 100 Days
Hello Aspirant,
P(1)*V(1)/T=P(2)*V(2)/T
20*1=P(2)*50
P(2)=0.4 atm
This formula is valid since the no. of moles did not change and is derived from Ideal gas equation PV=nRT
ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas. It is a good approximation of the behavior of many gases under many conditions, although it has several limitations. It was first stated by Émile Clapeyron in 1834 as a combination of the empirical Boyle's law, Charles's law, Avogadro's law, and Gay-Lussac's law.
Related Questions
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates BrochureYour Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.