Question : If $ABC \cong PQR$ and $\angle ABC = (x + 60)°$, $\angle PQR = (85 – 4x)°$, and $\angle RPQ = (3x + 65)°,$ then the value of $\angle ABC$ in degree is:
Option 1: 15°
Option 2: 5°
Option 3: 45°
Option 4: 65°
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 65°
Solution : $\angle ABC$ = ($x$ + 60)°, $\angle PQR = (85 - 4x)°$ If $\triangle$ABC ≅ $\triangle$PQR, ⇒ $\angle ABC =\angle PQR$ ⇒ $(x + 60)° = (85 -4x)°$ ⇒ $x+4x = 85 - 60$ ⇒ $5x = 25$ ⇒ $x = 5$ $\therefore$ $\angle ABC = 5+60 = 65°$ Hence, the correct answer is 65°.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $\cos x=\sin y$ and $\cot(x–40°)=\tan(50°–y)$, then the values of $x$ and $y$ are:
Question : If $\sec( 4x-50°)=\operatorname{cosec}( 50°-x)$, then the value of $x$ is:
Question : In a $\triangle$PQR, the side QR is extended to S. If $\angle$QPR = 72° and $\angle$PRS=110°, then the value of $\angle$PQR is:
Question : If it is given that for two right-angled triangles $\triangle$ABC and $\triangle$DFE, $\angle$A = 25°, $\angle$E = 25°, $\angle$B = $\angle$F = 90°, and AC = ED, then which one of the following is TRUE?
Question : $\triangle ABC$ and $\triangle PQR$ are two triangles. AB = PQ = 6 cm, BC = QR =10 cm, and AC = PR = 8 cm. If $\angle ABC = x$, then what is the value of $\angle PRQ$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile