Question : If $a+b+c=13$ and $a b+b c+c a=45$, find $a^2+b^2+c^2$.
Option 1: 79
Option 2: 65
Option 3: 57
Option 4: 85
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 79
Solution : Given: $a+b+c=13$ and $ab+bc+ca=45$ $a^2 + b^2 + c^2 = (a + b + c)^2 - 2 (ab + bc + ca)$ $= 13^2-2\times 45$ $= 169-90 = 79$ Hence, the correct answer is 79.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : Find the third proportional of 25 and 45.
Question : If $a + 5b = 13$ and $ab = 9$, then find the value of $a^2 + 25b^2$.
Question : If $a+b+c=5$ and $a^2+b^2+c^2=15$, then find the value of $a^3+b^3+c^3-3 a b c-27$.
Question : If $a^2+b^2+c^2=160$ and $a+b+c=16$, find $a b+b c+c a$.
Question : If $a+b+c=15$ and $a b+b c+c a=22$, then find the value of $a^2+b^2+c^2$.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile