Question : If $2^x+3^y=17$ and $2^{x+2}-3^{y+1}=5$, then:
Option 1: $x= 1, y = 3$
Option 2: $x = 3, y = 3$
Option 3: $x = 3, y = 2$
Option 4: $x = 1, y = 2$
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Correct Answer: $x = 3, y = 2$
Solution : $2^x+3^y=17$ $2^{x+2}-3^{y+1}=5$ By trial and error method, When $y = 2, x= 3$ $2^3+3^2=8+9=17$ $2^{3+2}-3^{2+1}=32–27=5$ Hence, the correct answer is $x = 3 $ and $y = 2$.
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