Question : If $2x-6\leq x-3$ and $1+3x<4x+4$, then $x$ can take which of the following values?
Option 1: 4
Option 2: –4
Option 3: –6
Option 4: 2
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Correct Answer: 2
Solution :
Given: $2x-6\leq x-3$ and $1+3x<4x+4$
Or, $2x-x\leq 6-3$ and $-4+1<4x-3x$
Or, $x\leq 3$ and $-3<x$
Or, $-3<x\leq 3$
Amongst all the given values, 2 satisfies the above condition.
Hence, the correct answer is 2.
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