Question : If $\sin (p+q)=1$ and $\cos (p-q)=\frac{\sqrt{3}}{2}$, then find $p$.
Option 1: 90°
Option 2: 80°
Option 3: 60°
Option 4: 120°
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Correct Answer: 60°
Solution :
Given: $\sin (p+q)=1$ and $\cos (p-q)=\frac{\sqrt{3}}{2}$
$\sin (p+q)=\sin 90°$ and $\cos (p-q)=\cos 30°$
⇒ $(p+q)=90°$ ------------(1)
And $(p-q)=30°$ --------- (2)
Adding equations (1) and (2), we have,
⇒ $2p=120°$
⇒ $p=60°$
Hence, the correct answer is 60°.
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