Question : If $a+b+c=15$ and $a b+b c+c a=22$, then find the value of $a^2+b^2+c^2$.
Option 1: 131
Option 2: 141
Option 3: 161
Option 4: 181
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 181
Solution :
Given:
$a+b+c=15$ and $a b+b c+c a=22$
$(a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)$
⇒ $(15)^2 = a^2+b^2+c^2+2(22)$
⇒ $225 = a^2+b^2+c^2+44$
⇒ $a^2+b^2+c^2 = 181$
Hence, the correct answer is 181.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.