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Question : If $3 x=\sec A$ and $\frac{3}{x}=\tan A$, then $9\left(x^2-\frac{1}{x^2}\right)$ is:

Option 1: $3$

Option 2: $9$

Option 3: $1$

Option 4: $\frac{1}{9}$


Team Careers360 21st Jan, 2024
Answer (1)
Team Careers360 22nd Jan, 2024

Correct Answer: $1$


Solution : We know that,
$\sec ^2A-\tan^2 A=1$
⇒ $(3x)^2-(\frac{3}{x})^2=1$
⇒ $9x^2-\frac{9}{x^2}=1$
⇒ $9\left(x^2-\frac{1}{x^2}\right)=1$
Hence, the correct answer is $1$.

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