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Question : If $a^2+b^2+c^2=14$ and $a+b+c=6$, then the value of $(ab+bc+ca)$ is:

Option 1: 11

Option 2: 12

Option 3: 13

Option 4: 14


Team Careers360 15th Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: 11


Solution : Given: $a^2+b^2+c^2=14$ and $a+b+c=6$.
On squaring the given equation $a+b+c=6$, we get,
$(a+b+c)^2=6^2$
⇒ $a^2+b^2+c^2+2(ab+bc+ca)=36$
Substitute the value of $a^2+b^2+c^2=14$ in the above equation and we get,
⇒ $14+2(ab+bc+ca)=36$
⇒ $2(ab+bc+ca)=22$
⇒ $(ab+bc+ca)=11$
Hence, the correct answer is 11.

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