Question : If $\sqrt{\frac{\mathrm{a}}{\mathrm{b}}}=\frac{8}{3}-\sqrt{\frac{\mathrm{b}}{\mathrm{a}}}$ and $a-b=10$, then the value of $ab$ is:
Option 1: $32 \frac{1}{7}$
Option 2: $32 \frac{3}{7}$
Option 3: $32 \frac{4}{7}$
Option 4: $32 \frac{2}{7}$
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Correct Answer: $32 \frac{1}{7}$
Solution : Given: $\sqrt{\frac{\mathrm{a}}{\mathrm{b}}}=\frac{8}{3}-\sqrt{\frac{\mathrm{b}}{\mathrm{a}}}$ ⇒ $\sqrt\frac{a}{b} + \sqrt\frac{b}{a} = \frac{8}{3}$ Squaring both sides, we have, ⇒ $\frac{a}{b}+\frac{b}{a}+2=\frac{64}{9}$ ⇒ $\frac{a^2 + b^2}{ab} = \frac{64-18}{9}$ ⇒ $a^2 + b^2 = \frac{46ab}{9}$ Now, $a-b=10$ Squaring both sides, ⇒ $a^2 + b^2 - 2ab = 100$ ⇒ $\frac{46ab}{9} - 2ab = 100$ ⇒ $46ab - 18ab = 900$ ⇒ $28ab = 900$ $\therefore ab = \frac{900}{28}=32\frac{1}{7}$ Hence, the correct answer is $32\frac{1}{7}$.
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