Question : If $2 x+5 y=15$ and $x y=6$, then the value of $4 x^2+25 y^2$ is:
Option 1: 105
Option 2: 95
Option 3: 100
Option 4: 90
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 105
Solution : Given, $2 x+5 y=15$ and $x y=6$ Consider, $2x+5y=15$ Squaring both sides, we get, ⇒ $(2x+5y)^2=15^2$ ⇒ $4x^2 + 25y^2 + 20xy = 225$ ⇒ $4x^2+25y^2+20×(6)=225$ ⇒ $4x^2+25y^2=225-120$ ⇒ $4x^2+25y^2 = 105$ Hence, the correct answer is 105.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If $x^3=270+y^3$ and $x=(6+y)$, then what is the value of $(x+y)? $(given that $x>0$ and $y>0$)
Question : If $6^{x}=3^{y}=2^{z}$, then what is the value of $\frac{1}{y}+\frac{1}{z}-\frac{1}{x}$?
Question : If ${x^2+y^2+z^2=2(x+z-1)}$, then the value of $x^3+y^3+z^3$ is equal to:
Question : If $x=(\sqrt{6}-1)^{\frac{1}{3}}$, then the value of $\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right)$ is:
Question : If $x(x+y+z)=20$, $y(x+y+z)=30$, and $z(x+y+z)=50$, then the value of $2(x+y+z)$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile