Question : If $\mathrm{K}+\frac{1}{\mathrm{~K}}+2=0$ and $\mathrm{K}<0$, then what is the value of $\mathrm{K}^{10}+\frac{1}{\mathrm{~K}^{11}}$?
Option 1: 1
Option 2: 0
Option 3: –1
Option 4: 2
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Correct Answer: 0
Solution : Given, $\mathrm{K}+\frac{1}{\mathrm{~K}}+2=0$ ⇒ $\mathrm{K}^2+1+2\mathrm{K}=0$ ⇒ $(\mathrm{K}+1)^2=0$ $\therefore \mathrm{K}=-1$ So, $\mathrm{K}^{10}+\frac{1}{\mathrm{~K}^{11}}=\mathrm{(-1)}^{10}+\frac{1}{\mathrm{(-1)}^{11}}=1-1=0$ Hence, the correct answer is 0.
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Question : If $\mathrm{K}+\frac{1}{\mathrm{~K}}+2=0$ and $\mathrm{K}<0$, then what is the value of $\mathrm{K}^{11}+\frac{1}{\mathrm{~K}^4}$?
Option 1: 0
Option 2: –2
Option 4: –17
Question : If $\mathrm{k}+\frac{1}{\mathrm{k}}=4$, then what is the value of $\mathrm{k}^4+\frac{1}{\mathrm{k}^4}$ ?
Option 1: 410
Option 2: 192
Option 3: 212
Option 4: 194
Question : What is the value of $ \left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}^8+\frac{1}{\mathrm{k}^8}\right)\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)? $
Option 1: $\frac{\mathrm{k}^{64}-\frac{1}{\mathrm{k}^{64}}}{\mathrm{k}+\frac{1}{\mathrm{k}}}$
Option 2: $\frac{\mathrm{k}^{32}-\frac{1}{\mathrm{k}^{32}}}{\mathrm{k}-\frac{1}{\mathrm{k}}}\\$
Option 3: $\frac{\mathrm{k}^{32}-\frac{1}{\mathrm{k}^{32}}}{\mathrm{k}+\frac{1}{\mathrm{k}}}\\$
Option 4: $\frac{\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}}{\mathrm{k}+\frac{1}{\mathrm{k}}}$
Question : If $x+\frac{1}{x}=-2$, then what is the value of $x^{17}+x^{-17}+x^{12}+x^{-12} ?(x<0)$
Option 1: –2
Option 2: –1
Option 3: 1
Option 4: 0
Question : Which of the following is correct?
Option 1: $\frac{2}{3}< \frac{3}{5}< \frac{11}{15}$
Option 2: $\frac{3}{5}< \frac{2}{3}< \frac{11}{15}$
Option 3: $\frac{11}{15}< \frac{3}{5}< \frac{2}{3}$
Option 4: $\frac{3}{5}< \frac{11}{15}< \frac{2}{3}$
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