Question : If $a + b = 24$ and $8ab = 256$, then what is the value of $3 a^2+3 b^2?$
Option 1: 1536
Option 2: 1024
Option 3: 512
Option 4: 1636
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 1536
Solution :
Given,
$a + b = 24$ and $8ab = 256$
⇒ $2ab=\frac{256}{4}=64$
We know, $(a+b)^2=a^2+b^2+2ab$
Consider $a + b = 24$
Squaring both sides,
⇒ $a^2+b^2+2ab=24^2$
⇒ $a^2+b^2+64=576$
⇒ $a^2+b^2=576-64$
⇒ $a^2+b^2=512$
⇒ $3a^2+3b^2=3\times 512$
⇒ $3a^2+3b^2=1536$
Hence, the correct answer is 1536.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.