Question : If $\small x+3y-\frac{2z}{4}=6, \; x+\frac{2}{3}(2y+3z)=33$ and $\frac{1}{7}(x+y+z)+2z=9,$ then what is the value of $46x+131y$?
Option 1: 414
Option 2: 364
Option 3: 384
Option 4: 464
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 414
Solution : Given: $x+3y-\frac{2z}{4} = 6$, $x+\frac{2}{3}(2y+3z) = 33\;$ and $\frac{1}{7}(x+y+z)+2z = 9$ Solution: $4x+12y-2z = 24......(i)$ $3x+4y+6z = 99.......(ii)$ $x+y+15z = 63........(iii)$ Multiplying equation (i) by 3, we get, $12x+36y-6z = 72......(iv)$ Now adding equation (ii) and (iv) we get, $15x+40y = 171.......(v)$ Multiplying equation (ii) by 5 and equation (iii) by 2 and then subtracting equation (iii) from (ii) $13x+18y = 369$.......(vi) Multiplying equation (v) by 9 and equation (vi) by 20 and then subtracting equation (v) from (vi), we get, $125x = 5841$ ⇒ $x = 46.728$ Putting the value of $x$ in the above equations, we will get, $y = –13.248$ Now, $46x+131y = 46×46.728+131×(–13.248) = 2149.488–1735.488 = 414$ Hence, the correct answer is 414.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $x+y+z=0$, then what is the value of $\frac{x^2}{3z}+\frac{y^3}{3xz}+\frac{z^2}{3x}$?
Question : The value of $\frac{(x-y)^3+(y-z)^3+(z-x)^3}{6(x-y)(y-z)(z-x)}$, where $x \neq y \neq z$, is equal to:
Question : If $x+y+z=0$, then what is the value of $\frac{\left (3y^{2}+x^{2}+z^{2} \right )}{\left (2y^{2}-xz \right)}$?
Question : If $\frac{3–5x}{2x}+\frac{3–5y}{2y}+\frac{3–5z}{2z}=0$, the value of $\frac{2}{x}+\frac{2}{y}+\frac{2}{z}$ is:
Question : If $x+y+z=0$, then what is the value of $\frac{x^2}{(y z)}+\frac{y^2}{(x z)}+\frac{z^2}{(x y)}$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile