Question : If $(x+y)^2=xy+1$ and $x^3-y^3=1$, what is the value of $(x-y)$?
Option 1: 1
Option 2: 0
Option 3: –1
Option 4: 2
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Correct Answer: 1
Solution : Given: $(x+y)^2=xy+1$ and $x^3-y^3=1$ Consider, $(x+y)^2=xy+1$ ⇒ $x^2+y^2+2xy-xy=1$ ⇒ $x^2+y^2+xy=1$ Now, we know, $x^3-y^3=(x-y)(x^2+xy+y^2)$ ⇒ $1=(x-y)×1$ $\therefore(x-y)=1$ Hence, the correct answer is 1.
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Question : If $x=1-y$ and $x^2=2-y^2$, then what is the value of $xy$?
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