if any ideal binary solution of a and b when equal mole fraction of A and B is present then the total pressure of reaction is 760mmhg.Vapur pressure of A in vapour 600mmhg then vapour pressure in pure state is
Answer (1)
2nd Aug, 2020
Hello,
Vapour pressure of A, Va = 600 mmhg ( Given)
Vapour pressure of reaction, V = 760 mmhg ( Given)
No. of moles of A, Xa = No. of moles of B, Xb = 0.5 (Given) [ Xa + Xb = 1]
Now applying Raoult's law, we have:
V = Va * Xa + Vb * Xb
We have to find, vapour pressure of B, Vb. Subsituting the values given, in the equation above, we get:
760 = 600 * 0.5 + Vb * 0.5
= Vb = 460/0.5 = 920
Therefore, Vapour pressure of B in pure state is: 920 mmhg (Answer)
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