Question : If A's salary is 40% less than that of B, how much percent is B's salary more than that of A?
Option 1: $33\frac{1}{3}\%$
Option 2: $66\frac{2}{3}\%$
Option 3: $33\frac{2}{3}\%$
Option 4: $66\frac{1}{3}\%$
Correct Answer: $66\frac{2}{3}\%$
Solution :
Given: A's salary is 40% less than B.
Let salary of B = 100 units
Then, salary of A = B – 40% of B = 100 – ($\frac{40}{100}$ × 100) = 60 units
Percentage of B's salary more than A $=\frac{B-A}{A} × 100 = (\frac{100–60}{60}) × 100 = 66\frac{2}{3}\%$
Hence, the correct answer is $66\frac{2}{3}\%$.
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