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if cos thita =12upon13 , 0
jaywadmare 1st Sep, 2020

Answer (1)
Leesa Das 1st Sep, 2020

cos theta =12/13

cos^2 theta= (12/13)^2

sin^2 theta = 1-(12/13)^2

= (169-144)/169

= 25/169

sin theta = 5/13

(sin ^2 theta - cos ^2 theta) / (2* sin theta *cos theta)

= 25-144 / 120

=-119/120

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