Question : If each edge of a square is doubled, then the increase percentage in its area is:
Option 1: 200%
Option 2: 250%
Option 3: 280%
Option 4: 300%
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Correct Answer: 300%
Solution : The area of a square = $s^2$, where $s$ is the length of a side. If the side length is doubled, the new area = $(2s)^2 = 4s^2$ The increase in area = $4s^2 - s^2 = 3s^2$ The percentage increase in area $=\frac{3s^2}{s^2} \times 100=300$% Hence, the correct answer is 300%.
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Question : The length and breadth of a rectangle are doubled. Percentage increase in area is:
Question : Let A be the area of a square whose each side is 10 cm. Let B be the area of a square whose diagonals are 14 cm each. Then (A – B) is equal to:
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