Question : If each side of an equilateral triangle is 12 cm, then its altitude is equal to:
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $3 \sqrt{6}\ \text{cm}$
Option 3: $6 \sqrt{2}\ \text{cm}$
Option 4: $3 \sqrt{2}\ \text{cm}$
Correct Answer: $6 \sqrt{3}\ \text{cm}$
Solution : We know that, The altitude of an equilateral triangle = $\frac{\sqrt3}{2}$ × side $= \frac{\sqrt3}{2} × 12 =6\sqrt3\ \text{cm}$ Hence, the correct answer is $6\sqrt3\ \text{cm}$.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : The radius of the incircle of the equilateral triangle having each side 6 cm is:
Question : The area of an equilateral triangle is $4 \sqrt{3} \mathrm{~cm}^2$. Find the side (in cm) of the triangle.
Question : The sides of a triangle are 8 cm, 12 cm, and 16 cm. What is the area of the triangle?
Question : In triangle ABC which is equilateral. O is the point of intersection of altitude AL, BM, and CN. If OA = 16 cm, what is the semi-perimeter of the triangle ABC?
Question : The altitude of an equilateral triangle of side $\frac{2}{\sqrt3}$ cm is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile