Question : If $\frac{1}{2}: x:: x: \frac{1}{8}$, find the positive value of $x$.
Option 1: $\frac{1}{25}$
Option 2: $\frac{1}{12}$
Option 3: $\frac{1}{4}$
Option 4: $\frac{1}{11}$
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{1}{4}$
Solution : Given: $\frac{1}{2}: x:: x: \frac{1}{8}$ ⇒ $x^2=\frac{1}{2}\times \frac{1}{8}$ ⇒ $x^2=\frac{1}{16}$ ⇒ $x=\frac{1}{4}$ Hence, the correct answer is $\frac{1}{4}$.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : If $8 : x :: x : 32$, find the positive value of $x$.
Question : The value of $\frac{1}{8} × \left[\frac{1}{5}\right.$ of $\left.\frac{11}{2} ÷\left\{\left(\frac{15}{3}-\frac{18}{6}\right)\right\}\right]$ is:
Question : If $x=-1$, then the value of $\frac{1}{x^{99}}+\frac{1}{x^{98}}+\frac{1}{x^{97}}+\frac{1}{x^{96}}+\frac{1}{x^{95}}+\frac{1}{x^{94}}+\frac{1}{x}-1$ is:
Question : If $A=\frac{2}{3} \div \frac{4}{9}, B=\frac{6}{11} \times\frac{33}{12}$ and $C=\frac{1}{3} \times \frac{9}{2}$, then what is the value of $A \times B-C$?
Question : If 16 : $x$ :: $x$ : 196, find the positive value of $x$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile