Question : If $\sec \theta=2 \frac{4}{23}$,find the value of $\tan^2 \theta$.
Option 1: $2 \frac{16}{529}$
Option 2: $1 \frac{200}{529}$
Option 3: $3 \frac{384}{529}$
Option 4: $3 \frac{177}{529}$
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: $3 \frac{384}{529}$
Solution :
Given:
$\sec \theta=2 \frac{4}{23}=\frac{50}{23}$
We know, $\tan^2\theta=\sec^2\theta-1$
⇒ $\tan^2\theta=(\frac{50}{23})^2-1$
⇒ $\tan^2\theta=\frac{2500}{529}-1$
⇒ $\tan^2\theta=\frac{1971}{529}$
$\therefore \tan^2\theta=3 \frac{384}{529}$
Hence, the correct answer is $3 \frac{384}{529}$.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
