Question : If $\frac{b}{a}=0.7$, find the value of $\frac{a–b}{a+b}+\frac{11}{34}$.
Option 1: 0.2
Option 2: 1
Option 3: 0.5
Option 4: 0.3
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Correct Answer: 0.5
Solution :
Given: The value of the ratio $\frac{b}{a}=0.7$.
The value of the expression $\frac{a–b}{a+b}+\frac{11}{34}$ is given as,
$=\frac{1–\frac{b}{a}}{1+\frac{b}{a}}+\frac{11}{34}$
Substitute the value of $\frac{b}{a}=0.7$ in the above expression,
$=\frac{1–0.7}{1+0.7}+\frac{11}{34}$
$=\frac{0.3}{1.7}+\frac{11}{34}$
$=0.17+0.33=0.5$
Hence, the correct answer is 0.5.
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