If four dice are thrown together then probability of getting prime numberson exactly two of them is
Dear Student,
N(Sample space )=(1,2,3,4,5,6)
Probability of getting prime number on exactly two dice
N(A)=(1,1),(1,2),(1,3),(1,5),(2,1),(2,2),(2,3),(2,5),(3,1),(3,2),(3,3),(5,1),(5,2),(5,3),(5,5)
N(probability)=N(A)/N(s)
Since the question is about two dice
So N(s)=36
So answer will be 15/36