if i got 109 marks in jee 2020 jan 7th shift 1 what is my percentile
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Hello! From last year JEE Mains is conducted two times in a year and therefore the rank of every student is based on both of his/her attempts. Therefore, we cannot get the exact rank but can try to calculate it using last year's data.
As you know that your percentile will be calculated shiftwise , so for calculating your percentile the formula we will use will be:
(No. of people having less than 109 marks in first shift/total number of students present in first shift)*100
So, considering last year's data your percentile can lie between 96.35511496 - 95.49744019. This will change according to various conditions like the difficulty of your paper or the no. of students appearing in your shift.
To calculate your rank we will use the formula:
1+((100-P) * No. of total students appearing)/100)
So your rank according to previous year's data will approximately be 18378 - 57131 . This will also vary according to different factors but this is the rough idea for your rank.
For more accurate rank prediction you can use our jee mains rank predictor:
You can check our jee mains pack to score even more higher in april attempt: https://learn.careers360.com/knockout-jee-main-april/
Hope it helps. All the best!
Your Overall Percentile is: 96.71 - 96.91
Your General Rank is: 28345 - 34495
At this percentile you will surely get clarify for jee advance but may not get seat in a good college.
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