Question : If, in a competitive exam, the marks obtained by Sam are 19% less than those of Peter, then the marks obtained by Peter are how much percentage more than the marks obtained by Sam? (Correct to two decimal places)
Option 1: 28.64%
Option 2: 22.25%
Option 3: 21.50%
Option 4: 23.46%
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Correct Answer: 23.46%
Solution :
Let the marks of Peter be $100$.
$\therefore$ Marks obtained by sam = $\frac{(100-19)}{100}\times 100=\frac{81}{100}\times 100 = 81$
Now, the percentage of marks obtained by Peter is more than that of Sam's
= $\frac{19}{81}\times 100$
= $23.46{\%}$
Hence, the correct answer is 23.46%.
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