Question : If in a $\triangle$PQR, $\angle$P = $88^\circ$, PQ and PR are produced to points S and T respectively. If the bisectors of $\angle$SQR and $\angle$TRQ meet at the point O. Find $\angle$QOR.
Option 1: $42^\circ$
Option 2: $46^\circ$
Option 3: $44^\circ$
Option 4: $48^\circ$
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Correct Answer: $46^\circ$
Solution :
$\angle QOR =90^\circ-\frac{1}{2}\angle P$
⇒ $\angle QOR =90^\circ-\frac{88}{2}=46^\circ$
Hence, the correct answer is $46^\circ$.
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