Question : If in a triangle ABC, BE and CF are two medians perpendicular to each other and if AB = 19 cm and AC = 22 cm then the length of BC is:
Option 1: 19.5 cm
Option 2: 26 cm
Option 3: 20.5 cm
Option 4: 13 cm
Correct Answer: 13 cm
Solution : Given: AB = 19 cm, AC = 22 cm BE and CF are perpendicular to each other. We know that AB 2 + AC 2 = 5(BC) 2 ⇒ 19 2 + 22 2 = 5(BC) 2 ⇒ 361 + 484 = 5(BC) 2 ⇒ 845 = 5(BC) 2 ⇒ (BC) 2 = 169 ⇒ BC = 13 cm Hence, the correct answer is 13 cm.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : If two medians BE and CF of a triangle ABC, intersect each other at G and if BG = CG, $\angle$BGC = $120^{\circ}$, BC = 10 cm, then the area of the triangle ABC is:
Question : For a triangle ABC, D and E are two points on AB and AC such that $\mathrm{AD}=\frac{1}{6} \mathrm{AB}$, $\mathrm{AE}=\frac{1}{6} \mathrm{AC}$. If BC = 22 cm, then DE is _______. (Consider up to two decimals)
Question : In $\triangle \mathrm{ABC}$, AB = AC, and D is a point on side AC such that BD = BC. If AB = 12.5 cm and BC = 5 cm, then what is the measure of DC?
Question : Let $\triangle ABC \sim \triangle RPQ$ and $\frac{{area}(\triangle {ABC})}{{area}(\triangle {PQR})}=\frac{4}{9}$. If AB = 3 cm, BC = 4 cm and AC = 5 cm, then RP (in cm) is equal to:
Question : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circumcircle of $\triangle$ ABC?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile