Question : If $X$ is 20% less than $Y$, then find the values of$\frac{Y–X}{Y}$ and $\frac{X}{X–Y}$.
Option 1: $\frac{1}{5}$ and $-4$
Option 2: $5$ and $-\frac{1}{4}$
Option 3: $\frac{2}{5}$ and $-\frac{5}{2}$
Option 4: $\frac{3}{5}$ and $-\frac{5}{3}$
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{1}{5}$ and $-4$
Solution : Let $Y$ = 100 Then, $X$ = 100 × 80% = 80 The value of $\frac{Y–X}{Y}$ is $\frac{100–80}{100}=\frac{20}{100}=\frac{1}{5}$ The value of $\frac{X}{X–Y}$ is $\frac{80}{80–100} = –\frac{80}{20}=–4$ Hence, the correct answer is $\frac{1}{5}$ and $-4$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If $\frac{x}{y}=\frac{4}{5}$, then the value of $(\frac{4}{7}+\frac{2y–x}{2y+x})$ is:
Question : Simplify the given expression and find the value for $x=-1$. $\frac{10 x^2+5 x+2 x y+y}{5 x+y}$
Question : If $2x-2(3+4x)<-1-2x>\frac{-5}{3}-\frac{x}{3}$; then $x$ can take which of the following values?
Question : If $x+\frac{1}{x}=0$, then the value of $x^{5}+\frac{1}{x^{5}}$ is:
Question : If $x=5$ ; $y=6$ and $z=-11$, then the value of $x^{3}+y^{3}+z^{3}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile