Question : If $\triangle PQR$ is right angled at Q, then what is the value of $\cos (P+R)$?
Option 1: 0.5
Option 2: 1
Option 3: 0.2
Option 4: 0
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Correct Answer: 0
Solution :
$\triangle$PQR is right angled at Q, then $\angle$Q = 90°
$\cos(P + R) = \cos(180° − Q)$ (Since the sum of the angle in a triangle is 180°)
⇒ $\cos(P + R) = \cos(180° − 90°)$
⇒ $\cos(P + R) = \cos 90°$
Since, $\cos 90° = 0$
$\therefore \cos(P + R) = 0$
Hence, the correct answer is 0.
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