Correct Answer: 96 cm ²

Solution : Given,
$\triangle \mathrm{ABC}\sim \triangle \mathrm{DEF}$
$\mathrm{BC}=3 \mathrm{~cm}, \mathrm{EF}=4 \mathrm{~cm}$ and the area of $\triangle \mathrm{ABC}=54 \mathrm{~cm}^2$
⇒ $\frac{area(\triangle{ABC})}{area(\triangle{DEF})}=\frac{BC^2}{EF^2}$
⇒ $\frac{54}{area(\triangle{DEF})}=\frac{3^2}{4^2}$
⇒ $\frac{54}{area(\triangle{DEF})}=\frac{9}{16}$
⇒ $area(\triangle{DEF})=\frac{54\times16}{9}$
⇒ $area(\triangle{DEF})=96$ cm$^2$
Hence, the correct answer is 96 cm$^2$