Question : If $x$ is the mean proportional between 12.8 and 64.8, then the value of $x$ is:
Option 1: 32
Option 2: 34
Option 3: 28.8
Option 4: 26.4
Answer (1)
22nd Jan, 2024
Correct Answer: 28.8
Solution :
According to the question,
$c^2 = ab$
where $c$ is the mean proportion of $a$ and $b$.
Now, the mean proportion of 12.8 and 64.8
$x=\sqrt{12.8 \times 64.8}$
$=\sqrt{16 \times 0.8\times 0.8 \times 81}$
$=4 \times 0.8 \times 9$
$x=28.8$
Hence, the correct answer is 28.8.
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