if mid pouints are 5,15,25,35,45 and frequency is 3,9,8,5,3 and find the median\
Hi
Mid. Class. Freq. Cuml
point. Group. Freq
5 0-10 3 3
15 10-20 9 12
25 20-30 8 20
35 30-40 5 25
45 40-50 3 28
h= 15-5= 10
h/2 = 10/2=5
5+5 =10
5-5=0
Therefore class group for 5 midpoint is 0-10
Cumulative freq calculated as
Freq 3 is 3
Freq 9 is 3+9 =12
Freq 8 is 12+8=20...
Hence forth N = 28
N/2= 14
Cumulative freq closest to 14 is 12 hence class group is 10-20 and f=9
Median = l+(N/2-F)/f * h
l =10 (lower limit of 10-20)
F= 3 ( cumulative freq that comes before 12)
f=9
h=10( difference between 10-20)
Median= 10+(14-3/9)*10
=22.22approx
Get back to me again if you find any error here.
