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if mid pouints are 5,15,25,35,45 and frequency is 3,9,8,5,3 and find the median\


jashandeep singh 8th Sep, 2021
Answer (1)
Vidya Kasi 8th Sep, 2021

Hi

Mid.      Class.    Freq.   Cuml

point.    Group.               Freq

5           0-10        3          3

15         10-20      9         12

25          20-30     8         20

35         30-40       5         25

45        40-50       3          28


h= 15-5= 10

h/2 = 10/2=5

5+5 =10

5-5=0

Therefore class group for 5 midpoint is 0-10

Cumulative freq calculated as

Freq 3 is 3

Freq 9 is 3+9 =12

Freq 8 is 12+8=20...

Hence forth N = 28

N/2= 14

Cumulative freq closest to 14 is 12 hence class group is 10-20 and f=9

Median = l+(N/2-F)/f * h

l =10 (lower limit of 10-20)

F= 3 ( cumulative freq that comes before 12)

f=9

h=10( difference between 10-20)

Median= 10+(14-3/9)*10

=22.22approx


Get back to me again if you find any error here.


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