Question : If Mohan travels at 60% speed of his usual speed, then he will arrive 10 minutes late. What is the usual time taken by him?
Option 1: 12.5 minutes
Option 2: 15 minutes
Option 3: 10 minutes
Option 4: 20 minutes
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Correct Answer: 15 minutes
Solution : Given: Mohan travels at 60% = $\frac{3}{5}$ speed of his usual speed. Use the formula, $\text{Time}=\frac{\text{Distance}}{\text{Speed}}$. Let the man's speed be $5x$. ⇒ 60% of the speed = $5x\times \frac{3}{5}=3x$ Man's speed ratio before and after = $5x: 3x$ ⇒ The after and before time ratio = $3x: 5x$ According to the question, $5x-3x=10$ ⇒ $2x=10$ ⇒ $x=5$ minutes The usual time taken by him = $3x=3\times 5=15$ minutes. Hence, the correct answer is 15 minutes.
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