Question : If $\frac{2}{3}$ of A = 75% of B = 0.6 of C, then $A:B:C$ is:
Option 1: $2:3:3$
Option 2: $3:4:5$
Option 3: $4:5:6$
Option 4: $9:8:10$
Correct Answer: $9:8:10$
Solution : Given: $\frac{2}{3}$ of A = 75% of B = 0.6 of C Here, $\frac{2}{3}$ of A = 75% of B ⇒ $\frac{2A}{3}=\frac{75B}{100}$ ⇒ $\frac{A}{B}=\frac{9}{8}$ Let A and B be 9 and 8 respectively. Now, 75% of B = 0.6 of C ⇒ $\frac{75B}{100}=\frac{6C}{10}$ ⇒ $\frac{B}{C} =\frac{4}{5} =\frac{8}{10}$ So, $A:B: C = 9:8:10$ Hence, the correct answer is $9:8:10$.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : If $A+\frac{1}{1+\frac{1}{2+\frac{1}{3}}}=\frac{9}{10}$, then the value of A is:
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}+\frac{3}{4} \div \frac{1}{2}$ is:
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}-\frac{3}{4}+\frac{3}{4} \div \frac{1}{2}$ is:
Question : If A : B = 3 : 4 and B : C = 6 : 5, then A : ( A + C) is equal to:
Question : If $p=\frac{5}{18}$, then $27p^{3}–\frac{1}{216}–\frac{9}{2}p^{2}+\frac{1}{4}p$ is equal to:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile