If S is a set with 10 elements and A={(x,y):x,y belongs to S x not equal to y} then the number of elements in A in
According to me there are 10*9 = 90 elements in the SET A,because if the tuple of the element is such that x != y then you can put the 10 elements at the first place and remaining 9 elements on the second place in the tuple.
By the basic principle of counting / permutation it is nothing but 10*9 = 90 elements possible in the SET A.
Hope it Helps :)