Question : If $\triangle A B C \sim \triangle E D F$ such that $AB=6$ cm, $DF=16$ cm, and $DE=8$ cm, then the length of $BC$ is:
Option 1: 12 cm
Option 2: 10 cm
Option 3: 14 cm
Option 4: 8 cm
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Correct Answer: 12 cm
Solution :
Given, $\triangle A B C \sim \triangle E D F$ such that $AB=6$ cm, $DF=16$ cm and $DE=8$ cm
As $\triangle ABC$ ~ $\triangle EDF$
⇒ $\frac{AB}{DE} = \frac{BC}{DF}$
⇒ $\frac{6}{8} = \frac{BC}{16}$
$\therefore BC= 12$ cm
Hence, the correct answer is 12 cm.
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