Question : If the area of the non-spherical portion of a solid hemisphere is 1,560 m2, then the total surface area of the hemisphere is:
Option 1: 6,240 m2
Option 2: 4,680 m2
Option 3: 5,140 m2
Option 4: 3,120 m2
New: SSC MTS Tier 1 Answer key 2024 out
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 4,680 m2
Solution : Given: The area of the non-spherical portion of a solid hemisphere is 1560 m2. So, $\pi r^2=1560$ --------------(1) The total surface area of the hemisphere = $3\pi r^2$ where $r$ is the radius. Substitute the value of $\pi r^2$ from the equation (1), ⇒ $3\pi r^2=3\times 1560=4,680$ m2 Hence, the correct answer is 4,680 m2.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : The curved surface area is thrice as big as the base area of a cone. If the diameter of the cone is 1 cm. Then what is the total surface area (in cm2) of the cone?
Option 1: $\pi$
Option 2: $3\pi $
Option 3: $2\pi$
Option 4: $4\pi $
Question : Find the surface area of a spherical ball that has a radius of 1.1 cm.
Option 1: 16 cm2
Option 2: 12.1 cm2
Option 3: 11.2 cm2
Option 4: 15.2 cm2
Question : The side of a square is equal to 40% of the radius of a sphere. If the volume of the sphere is $\frac{500 \pi}{3} \mathrm{~m}^3$, then what is the area of the square?
Option 1: 2 m2
Option 2: 1 m2
Option 3: 9 m2
Option 4: 4 m2
Question : If the volume of a cube is 5832 cm3, then what is the lateral surface area of this cube?
Option 1: 1024 cm2
Option 2: 384 cm2
Option 3: 576 cm2
Option 4: 1296 cm2
Question : If the sum of the length, breadth and height of a rectangular parallelepiped is 24 cm and the length of its diagonal is 15 cm, then its total surface area is:
Option 1: 256 cm2
Option 2: 265 cm2
Option 3: 315 cm2
Option 4: 351 cm2
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile