Question : If the average of 41 consecutive odd numbers is 49, what is the largest number?
Option 1: 89
Option 2: 91
Option 3: 93
Option 4: 95
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 89
Solution : The average of 41 consecutive odd numbers is 49. Since the average of an arithmetic progression (AP) with an odd number of terms is the same as its middle term, Middle term = 21 st term = 49 Largest number = last term = 41 st term = 21 st term + (20 × 2) = 49 + 40 = 89 Hence, the correct answer is 89.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : The average of four consecutive odd numbers is 40. What is the largest number?
Question : The average of three consecutive odd numbers is 52 more than $\frac{1}{3}$rd of the largest number. What is the smallest of these numbers?
Question : The average of eight consecutive odd numbers is 48. Find the sum of the fifth and seventh numbers.
Question : The average of seven consecutive numbers is 20. The largest of these numbers is:
Question : If the average of 6 consecutive even numbers is 25, the difference between the largest and the smallest number is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile