Its 66. Take first even number as a , second as a+2 , third as a+4, fourth as a+6 , fifth as a+8 , sixth as a+10 . (As all are consecutive numbers) so taking sum of all numbers and divide it by 6 and equal to 25 . Value a was found to be 20. Now finding sum of first three numbers by putting value of a to it.
Hope it helps . Thank you
Hello Aspirant
The average of 6 consecutive even numbers can never be 25. So, please correct your question.
I hope you will resend your question.
Thanks
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