if the circle X square + y square - 4 x + 6 y + y is equals to zero has radius 4 find a
hello student,
Here is the solution.
So, the equation is
X^2+Y^2-4X+7Y =0 ---------------------------------------------------------------------------------------(I)
Radius = 4
We need to find a.
((X-2)^2-4)+((Y+3.5)^2-12.25)=0
(X-2)^2+(Y+3.5)^2 = 16.25 ----------------------------------------------------------------------------(1)
Since radius is given as 4, this 16.25 is rounded to 16
SO the actual equation is X^2+Y^2=R^2
Which is modified to:
(X-a)^2+(Y+b)^2 = R^2 ---------------------------------------------------------------------------------(2)
Comparing equation (1) with equaltion (2)
R= 4,
a=2
Therefore a=2