Correct Answer: Area of the circle > Area of the square

Solution : Let the radius of the circle be '$r$' and side of the square be 'a'
Since the perimeter of a square = circumference of a circle
⇒ 4a = 2$\pi r$
⇒ ​​​​​a = $\frac{\pi r}{2}$
⇒ Area of Square = $(\frac{\pi r}{2})^{2}$
⇒ $\frac{\text{Area of circle}}{\text{Area of square}} =  \frac{\pi r^{2}}{(\frac{\pi r}{2})^{2}}=\frac{4}{\pi}$​​​​​​ > 1
So, the area of the circle > the area of the square.
Hence, the correct answer is Area of the circle > Area of the square.