Question : If the diagonals of a Rhombus are 12 cm and 16 cm, then what is the perimeter (in cm) of the Rhombus?
Option 1: 20 cm
Option 2: 40 cm
Option 3: 60 cm
Option 4: 80 cm
Correct Answer: 40 cm
Solution : The diagonals of a rhombus are 12 cm and 16 cm. We know that diagonals perpendicularly bisect each other in a rhombus. Side of a rhombus = $\sqrt{(\frac{\text{Diagonal_1}}{2})^2 + (\frac { \text{Diagonal_2}}{2})^2}$ ⇒ Side of rhombus = $\sqrt{(\frac{12}{2})^{2}+ (\frac{16}{2})^{2}}$ ⇒ Side = $\sqrt{36+64} = \sqrt{100} = 10$ cm $\therefore$ Perimeter = 4 × 10 = 40 cm (Since all sides are equal in a rhombus) Hence, the correct answer is 40 cm.
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Question : If the diagonals of a rhombus are 16 cm and 30 cm. What is the perimeter (in cm) of the rhombus?
Question : If the diagonals of a Rhombus are 16 cm and 30 cm. What is the perimeter (in cm) of the Rhombus?
Question : If the perimeter of a rhombus is 40 cm and one of its diagonals is 16 cm, what is the area (in cm2) of the rhombus?
Question : If the perimeter of a rhombus is 80 cm and one of its diagonals is 24 cm, then what is the area (in cm2) of the rhombus?
Question : If the perimeter of a square is $80\;\mathrm{cm}$, then what is the diagonal (in $\mathrm{cm}$) of the square?
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