Question : If the diagonals of a Rhombus are 16 cm and 30 cm. What is the perimeter (in cm) of the Rhombus?
Option 1: 32
Option 2: 64
Option 3: 34
Option 4: 68
Correct Answer: 68
Solution : The diagonals of a Rhombus are 16 cm and 30 cm. We know diagonals perpendicularly bisect each other in a Rhombus. Side of Rhombus = hypotenuse of the triangle formed by the halves of the diagonals. Side of Rhombus = $\sqrt{(\frac{16}{2})^{2}+ (\frac{30}{2})^{2}}$ Side = $\sqrt{82+152} = \sqrt{289} = 17$ cm $\therefore$ Perimeter = 4 × 17 = 68 cm (Since all sides are equal in a Rhombus.) Hence, the correct answer is 68 cm.
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Question : If the diagonals of a rhombus are 16 cm and 30 cm. What is the perimeter (in cm) of the rhombus?
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Question : Find the area of a rhombus if the perimeter of the rhombus is 52 cm, and one of its diagonals is 10 cm long.
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